Question

3. Transform the following equations into (a) slope-intercept form (b) intercept form and (c)normal
form
(a) 3x+4y = 5
(b) 4r-3y+ 12 = 0
(c)√3+y=4
) x+y-2 = 0
(iv) x+y+2 = 0
(vi) √
3x + y + 10 = 0​

Answer 1

Given : equations

a) 3x+4y = 5

(b) 4r-3y+ 12 = 0

To Find :  Transform the following equations into

a) slope-intercept form

(b) intercept form and

(c)normal  form

Solution:

slope-intercept form  :  y=mx+b  

intercept form x/a  + y/b  = 1

normal  form   ax + by + c = 0

3x+4y = 5

slope-intercept form  :  y = (-3/4)x  + 5/4

intercept form x/(5/3)  + y/(5/4)  = 1

normal  form   3x + 4y - 5 = 0

4x-3y+ 12 = 0

slope-intercept form  :  y = (4/3)x  + 4

intercept form x/-3  + y/4  = 1

normal  form   4x + (-3)y + 12 = 0

Similarly other Can be written

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