Question

3. Two bodies are dropped from rest from two different buildings; one at a
height 200 m and another at a height of 150 m above the ground. What
will be the difference in height of the bodies after they have fallen for 2 s?
(g = 10 m/s)​

Answer 1

Answer:

50

Explanation:                              for Ist object. u =0. t=2sec

the object is 150m abobe the ground

a =g= 10 (9.8)

s=ut+1/2at^2

s=0×2+1/2×10×2×2

s=20

AFTER 2SECOND THE DISTANCE BETWEEN OBJECT AND GROUND IS. 150-20=130M

for IInd object. u =0. t=2sec

a =g= 10 (9.8)

the object is 100m abobe the ground

a =g= 10 (9.8)

s=ut+1/2at^2

s=0×2+1/2×10×2×2

s=20

AFTER 2SECOND THE DISTANCE BETWEEN OBJECT AND GROUND IS. 100-20=80M

THE DISTANCE BETWEEN THE OBJECTS AFTER 2 SEC

===130-80=50