Question

3. Two chairs and one table cost Rs.400, while
one table and one chair cost Rs.300. What is
the price of the table?​

Answer 1

$\huge{\blue{\bold{\underline{\underline{Answer :}}}}}$

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$\large{\green{\underline \bold{\tt{Given :-}}}}$

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• Two chairs and one table cost Rs.400

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• One table and one chair cost Rs.300

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$\large{\red{\underline \bold{\tt{To \: Find :-}}}}$

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• Price of the table

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$\large{\orange{\underline{\tt{Solution :-}}}}$

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• Let the price of 1 table be "x"

• Let the price of 1 chair be "y"

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$\purple{\underline \bold{According \: to \: the \ question :}}$

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Two chairs and one table cost Rs.400

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➜ x + 2y = 400 ------ (1)

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Also given that , One table and one chair cost Rs.300

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➜ x + y = 300 ------ (2)

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⟮ Subtracting equation (2) from (1) ⟯

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➜ x + 2y - (x + y) = 400 - 300

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➜ x + 2y - x - y = 100

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➨ y = 100 ------- (3)

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• Hence the price of 1 chair is Rs 100

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⟮ Putting y = 100 from (3) to (2) ⟯

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➜ x + y = 300

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➜ x + 100 = 300

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➜ x = 300 - 100

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➨ x = 200

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• Hence the price of 1 table is Rs 200

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∴ The price of 1 table and 1 chair is Rs 200 & Rs 100 respectively

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Answer 2

Answer :

›»› The price of the table is Rs.200.

Given :

• Two chairs and one table cost Rs.400, while one table and one chair cost Rs.300.

To Find :

• The price of the table.

Solution :

Let us assume that, the price of one table is "x" and the price of one chair is "y" respectively.

As it is given that, two chairs and one table cost Rs.400.

→ x + 2y = 400 .......(1)

As it is also given that, one table and one chair cost Rs.300.

→ x + y = 300 ........(2)

Our equation are,

• x + 2y = 400 .......(1)
• x + y = 300 ........(2)

Subtract equation (2) from equation (1),

→ (x + 2y) - (x + y) = 400 - 300

→ x + 2y - x - y = 400 - 300

→ x - x + 2y - y = 400 - 300

→ 2y - y = 400 - 300

→ y = 400 - 300

→ y = 100

Now, substitute the value of y in equation (2),

→ x + y = 300

→ x + 100 = 300

→ x = 300 - 100

→ x = 200

Hence, the price of the table is Rs.200.