Question

3. Two coins are tossed simultaneously. Find the probability of getting
(i) exactly 1 head (ii) at most 1 head (iii) at least 1 head.​

Answer 1

TH , HT , TT , HH

total outcomes = 4

(i)P (getting exactly 1 head) =2/4=1/2

(ii)P (getting at most 1 head)=3/4

[ TH , HT , TT ]

(iii)P (getting atleast 1 head) =3/4

[ HH , TH , HT ]