3. Two forces F1 = F2 are applied on a wheel of radius 1.5 m, such that moment of couple is 30 Nm. Calculate the magnitude of each of the
force.
Answers
Answered by
1
Answer:
20 N
Explanation:
t=r×f
30=1.5×f
f=20 N
Answered by
1
Answer:
Moment of couple= F×perpendicular distance× diameter
30Nm = F× 1.5m ×2
F= 30Nm / 3m
= 10 N
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