Question

3. Two forces F1 = F2 are applied on a wheel of radius 1.5 m, such that moment of couple is 30 Nm. Calculate the magnitude of each of the
force.​

Answer 1

Answer:

20 N

Explanation:

t=r×f

30=1.5×f

f=20 N

Answer 2

Answer:

Moment of couple= F×perpendicular distance× diameter

30Nm = F× 1.5m ×2

F= 30Nm / 3m

= 10 N

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