3. two forces of magnitude 5N and 10N are incligned with each other by 30 degree.what is the magnitud and direction of the resultant
Answers
Answered by
1
R² = 5² + 10² + 2 *5* 10 cos 30
= 125 + 50 √3
R = 211.6 N
Direction tan α = Q sin 30 / ( P + Q cos 30)
= 10 * 0.5 / (5 + 10 √3/2) => α = 20.1 deg
R makes α = 20.1 degrees with the line of force 5 N, towards the 10 N force.
= 125 + 50 √3
R = 211.6 N
Direction tan α = Q sin 30 / ( P + Q cos 30)
= 10 * 0.5 / (5 + 10 √3/2) => α = 20.1 deg
R makes α = 20.1 degrees with the line of force 5 N, towards the 10 N force.
Similar questions