Physics, asked by manojdanaboina67, 5 months ago

3. Two resisters R, 12, 422 are connected in series in a circuit. If the resultant resistance in the
circuit is 902 find the Value of Ri?

Answers

Answered by mantupravin

0

Answer:

468 ohm

Explanation:

equivalent resistance in series(R) = R1+R2+R3+........

according to given question

R+12+422=902

R+434=902

R=468 ohm

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