Question

3. Two resistors3Ωand 6Ωare connected first in series and then inparallel. The
ratio of the effective resistors will be ​

Answer 1

Explanation:

When connected in series:

Rs=3 ohm+6ohm =9ohm

when connected in parallel:

1/Rp= 1/3 ohm + 1/6ohm

Rp = 2ohms

Rs/Rp = 9/2

Answer 2

Answer:

in series:9 ohm and in parallel:2

Explanation:

in series R=r1+r2

=3+6=9

in parallel 1/R=1/R1+1/R2

=1/3+1/6

=1/2

=2