Question

3. Two vehicles CA and B) having mass 400kg and 600kg respectively have occupied the ssame surface са area on a road. Compare the pressure exerted by the vehicles on the surface​

Answer 1

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Answer 2

Answer:

Hence Pressure exerted by A $\frac{2}{3}$ of pressure exerted by B.

Explanation:

Mass of vehicle A is =400kg, Hence force exerted by A on the surface=mg

$F_1=mg=400*10=4000N$,

Similarly

Mass of vehicle B is =600kg,

$F_2=600*10=6000N$

Both the vehicles exert pressure on the same surface area.

Pressure exerted by the vehicle is defined as force per unit area, let us say

$P_1=\frac{F_1}{A}=\frac{4000}{A}\\\\P_2=\frac{F_2}{A}=\frac{6000}{A}$

Since A is same we can see that $\frac{P_1}{P_2}=\frac{4000}{6000}=\frac{2}{3}$, Hence Pressure exerted by A $\frac{2}{3}$ of pressure exerted by B.