3)Usha swims in a 90 m long pool. She covers 180 m in one minute by swimming from one end to the other and back along the same straight path. Find the average speed and average velocity of usha
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total distance=90+90
=180m
total time=1 minute
= 60seconds
speed. = distance traveled÷ total time taken
=180÷60
=3m/s
displacement=0m
time taken. =60seconds
velocity = displacement ÷ time taken
= 0÷60
=0m/s
therefore, speed=3m/s and velocity=0m/s
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