3. Using a suitable identity, evaluate: a) 91²-9² b) 999²
plz answer in sum
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Answer:
91²-9²
= (91+9)(91-9)
= 100×82
= 8200
999²
= (1000-1)²
= (1000)²-2.1000.1+(1)²
= 1000000-2000+1
= 998001
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