Question

3) using
suitable algebraic identity find 99
$99 {}^{2}$


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Answer 1

Step-by-step explanation:

We have,

$(99)^{2} = {(100 - 1)}^{2}$

$= {(100)}^{2} + {(1)}^{2} - 2 \times 100 \times 1$

$= 10000 + 1 - 200$

$= 9800 +1$

$= 9801$