Math, asked by neetmaster8, 9 months ago

3
value of (-2)^5 (-2)^3 ÷
2^10​

Answers

Answered by dikshaverma4you
4

FIND THE VALUE

Given :-

\frac{(-2)^{5} * (-2)^{3} }{2^{10} }

Solution :-

=\frac{(-2)^{5} * (-2)^{3} }{2^{10} }\\\\=\frac{(-2)^{8} }{2^{10} }\\\\ =(-1)^{8} * 2^{8} * 2^{(-10)}\\\\ =1*2^{(8+(-10))} \\\\=2^{(8-10)}\\\\=2^{(-2)}\\\\=\frac{1}{2^{2} }\\\\=\frac{1}{4}\\\\ = 0.25

Identities used above are :-

a^{m} * a^{n} = a^{(m+n)}\\\\\frac{a^{m} }{a^{n} } = a^{(m-n)}

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