3. Verify a x (b + c) = (a x b) + (a X c)
a=-1/2, b=4/3, c=-2/7
Answers
Answer:
Distributive property a×(b+c)=(a×b)+(a×c)
(1) a= -1/2 b=2/3 c=-5/6
To find:
We have to verify the distributive property for the given a,b,c values
Solution:
The given distributive property is a×(b+c) = (a×b)+(a×c)
Let us substitute the given values in above equation
(\frac{-1}{2})(
2
−1
) × (\frac{2}{3}+ \frac{-5}{6} )(
3
2
+
6
−5
) = (\frac{-1}{2}(
2
−1
× \frac{2}{3} )
3
2
) + (\frac{-1}{2}(
2
−1
× \frac{-5}{6} )
6
−5
)
(\frac{-1}{2})(
2
−1
) × (\frac{(2)(2) + (1)(-5)}{6} )(
6
(2)(2)+(1)(−5)
) = (\frac{-2}{6} )(
6
−2
) + (\frac{5}{12} )(
12
5
)
(\frac{-1}{2})(
2
−1
) × (\frac{4-5}{6} )(
6
4−5
) = \frac{(2)(-2)+(1)(5)}{12}
12
(2)(−2)+(1)(5)
(\frac{-1}{2})(
2
−1
) ×(\frac{-1}{6} )(
6
−1
) = \frac{-4+5}{12}
12
−4+5
\frac{1}{12}
12
1
= \frac{1}{12}
12
1
L.H.S = R.H.S
Hence verified.