Question

3 Verify whether the values of x given in each case are the zeroes of the polynomial
q:- f(x)=3x²-1;x=-1/√3,2/√3.​

Answer 1

Answer:

Step-by-step explanation:

f(x) = 3x² - 1

$f(-\frac{1}{\sqrt{3}})=3(-\frac{1}{\sqrt{3}})^{2}-1 = 0$ ⇒ $x = -\frac{1}{\sqrt{3}}$ is a zero of the polynomial.

$f(\frac{2}{\sqrt{3}}) = 3(\frac{2}{\sqrt{3}})^{2} -1 = 3$ ⇒ $x= \frac{2}{\sqrt{3}}$ is not a zero of polynomial.