3 vertices of a parallelogram taken in order are (1,2) (2,4) (3,7) find its 4th vertex
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A [1,2] B [2,4] C [3,7 ] let D [x,y]
In a parallelogram mid points of diagonal are same
so midpoint of AC = midpoint of BD
[ [ (1+3) /2 , (2+7) /2] = [ (2 + x) /2 , (4 + y) /2 ]
[ 4 /2 , 9 /2] = [ (2 + x) /2 , (4 + y) /2 ]
[ 2 , 9/2] = [ (2 + x) /2 , (4 + y) /2 ]
(2 + x) /2 =2 and (4 + y) /2 = 9/2
2 +x = 4 and 4 + y = 9
x =2 and y =5
D [2 ,5]
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