Question

3. Vijay had some bananas and he divided them into two lots A and B. He sold the first
lot at the rate of 2 for 3 bananas and the second lot at the rate of 1 per banana and
got a total of 400. If he had sold the first lot at the rate of · 1 per banana and the
second lot at the rate of 4 for 5 bananas, his total collection would have been * 460.
Find the total number of bananas he had.​

Answer 1

Answer:

here is your answer

Step-by-step explanation:

Let the first lot =x and the second lot =y, both in Rs .

∴ total number of bananas =x+y

In the first case price of x bananas at the rate of Rs. 2 per 3 bananas =

3

2x

and price of y bananas at the rate of Rs. 1 per banana =y.

∴ by the given condition

3

2x

+y=400

⇒2x+3y=1200 ..............(i)

In the second case price of x bananas at the rate of Rs. 1 per banana =x and price of y bananas at the rate of Rs. 4 per 5 banana =

5

4

y

∴ by the given condition x+

5

4

y=460

⇒5x+4y=2300 ........(ii)

Multiplying (i) by 5 and (ii) by 2, we get

10x+15y=6000 ........(iii) and 10x+8y=4600 .........(iv)

Subtracting (iv) from (iii), we get

7y=1400

⇒y=200

Putting y=200 in (i), we get

2x+3×200=1200

⇒x=300

∴x+y=300+200=500

So, Vijay had 500 bananas.

HOPE THIS HELPS U

Answer 2

Answer is in the above picture.

hope it helps