Question

3% ( w/v) aqueous solution of glucose would be isotonic with​

Answer 1

Disclaimer:

The complete question must be:

3% solution of glucose is isotonic with 1% solution of a non-volatile non-electrolyte substance. The molecular mass of the substance should be

(a) 180  (b) 360  (c) 420  (d) 60

Concept:

Isotonic compounds are defined as the compounds having the same tone i.e, the compounds having the same concentration.

Given:

The glucose solution of 3% (w/v) is isotonic with a 1% solution of a non-volatile non-electrolyte substance.

Find:

The molecular mass of the non-volatile non-electrolyte.

Solution:

As the solutions are isotonic, they are having equal concentrations.

Let, the molecular mass of the substance is y.

Concentration of 3% glucose = Concentration of 1% non-electrolyte

Molarity of 3% glucose = Molarity of 1% non-electrolyte

3/180 ×1000/100 = 1/y ×1000/100

3/180=1/y

y=180/3 = 60

Hence, the molecular mass of the substance is 60.

Hence, the correct option is (d) 60.

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