Question

3 wala question slove krodo koi pls​

Answer 1

Answer:

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Answer 2

Answer:

We have A(5,2) ,B(-7,2), C(6,3)

Step-by-step explanation:

Let us assume the points :A(x1, y1), B(x2, y2), C(x3, y3).

For collinear points, we have the formula:

1/2|x1(y2-y3)+x2(y3-y1)+x3(y1-y2)|=0

[this should be equal to zero]

Now, put the value in the formula,

1/2|5(2-3)+(-7)(3-2)+6(2-2)|

1/2|5(-1)+(-7)(1)+6(0)|

1/2|-5-7+0|

1/2|-12|

1/2(12) [:. | |mod convert all negative values to positive]

6

But 6 is not equal to zero. So, the points A, B and C are not collinear.

Hope you find it useful...

Thanku