Question

3. We know in a triangle sum of any two sides is greater than the third side. Is the sum of
any two angles of a triangle also greater than the third angle? Justify or contradict with an
example.
plzz full solution​

Answer 1

Answer:

Let ABC be a triangle, 

We can extend BA past A into a straight line,

Then there is a point D such that DA=CA

Therefore, from Isosceles triangle has two equal angles,

∠ADC=∠ACD

Thus, in △DCB, 

∠BCD>∠BDC (Side opposite greater angle is larger)

Thus, BD>CD

BA+AD>CD (Since, AC=AD)

BA+AC>CD

The sum of any two sides of the triangle is greater than the third side.

Answer 2

Step-by-step explanation:

No! it's not necessary. The sum of any 2 angles of a triangle, may be equal, greater or shorter than the third angle.

Like… out of 3 angles of triangle ( 50°, 30°, 100°)

50° + 30° < 100°

100° + 30° > 50°

100° + 50° > 30°

& 60deg + 30deg = 90deg

BUT, the sum of any 2 sides of a triangle is always > third side.