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what are the roots of quadratic eqution x3-9x+20-0
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Answer:
x3 - 9x + 20 - 0
x3-9x+20-0 = 0
x3-9x+20 = 0
x3-9x = -20
9x-3x = -20
6x = -20
x = -20/6
x = 10/3
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