Physics, asked by ashatalekar4, 11 months ago


3. What is the cost of running an AC with the average power of 1000 W for 6 hours for 30 days? The cost of electric energy is Rs 8.60 per kWh.

Answers

Answered by kshtijrawat177
3

Answer:

total numbers of hours = 30X24/6

avrage power = 1000W(given)=1kw [1000w=1kw]

consumed energy = 30X24/6X1

=140kwh

tere for cost to be paid = 140 X 8.6=1204

therefore cost to be paid =Rs 1204

Explanation:

Answered by handgunmaine
3

The cost of running an AC is 1548 Rs .

Given :

Average power , P = 1000 W .

Time running per day , t = 6 hours .

Number of days for which it runs , n = 30 days .

Also , cost of electric energy is Rs 8.60 per kWh .

Now , daily power consumption :

1000\times 6 = 6000\ watt \ hours=6 \ Kwh .

Daily cost ,

c=6\times 8.6\\c=51.6\ Rs

Therefore , monthly cost be :

C=30\times c\\C=30 \times 51.6\\C=1548\ Rs

Hence , this is the required solution .

Learn More :

Power and Energy

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