Question

3) What is the force constant of a spring which is stretched
a. 2mm by a force of 4 N,
b. 4cm by a mass of 200g?​

Answer 1

x=2cm

energy stored=

2

1

kx

2

100=0.5×k×2

2

k=

2

100

=50

now.x=4cm

energy stored =

2

1

kx

2

=0.5×50×4

2

=400J

so stored energy increases by=400−100=300