3. What is the greatest number which will divide 110 and 128 leaving a remainder 2 in each case?
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6
Answer:
Subtract remainder 2 from given numbers then find HCF
After subtracting 2 we get
108 and 126
126 = 2 × 3 × 3 × 7
108 = 2 × 2 × 3 × 3 × 3
HCF = 2 × 3³ = 18
18 is the largest number which divides 110 and 128 leaving a remainder 2 in each case
Answered by
1
answer.. when you divide 110 and 128 by 6 then remainder will be 2
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