Question

3. What is the magnitude of force on a wire of length
0.04 m placed inside a solenoid near its centre,
making an angle of 30° with its axis? The wire
carries a current of 12 A and the magnetic field due
to the solenoid is of magnitude 0.25 T.​

Answer 1

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GIVEN THAT;

$&#10146$ A wire of length (l) 0.04 m placed inside a solenoid near its center, making an angle of 30° with axis carries current (i) 12 A and magnetic field (B) due to the solenoid is of magnitude 0.25 T.

FORMULA

$&#10145 \: \: F = iBl \sin( \theta)$

where,

F = force

i = current

B = magnetic field

l = length of wire

θ = Angle

SOLUTIONS

$&#10145 \: \: F = iBl \sin( \theta) \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \\ \\ &#10230 \: \: F = 12 \times 0.25 \times 0.04 \times \sin(30) \\ \\ &#10230 \: \: F = \cancel{0.12} \times \frac{1}{\cancel2} \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \\ \\ &#10230 \: \: F = 0.06 \: N \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \:$

Answer 2

Answer:

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