Question

3.
What is the mass of CO2 produced from 50 g CaCO3?
(a) 11 g
(b) 22 g (c) 44 g​

Answer 1

Answer:

Answer is (b) 22 g

Explanation:

CaCO3--->CaO+CO2

Molecular mass of CaCO3 is 100 g

given mass of calcium carbonate is 50 g

So, moles of calcium carbonate is 50/100=0.5 moles

So, one mole of calcium carbonate gives 1 mole of CO2

Therefore 0.5 mole of calcium carbonate gives 44*0.5==>22 g of CO2

I hope this will help you