Question

3, What is the other end of the diameter of the circle whose center is (1,2) and one endpoint is (3,4)​

Answer 1

Answer:

[ -1,0 ]

Step-by-step explanation:

step-by-step explanation:

Given,

a circle

whose centre is point O.

also,

let,

AB be its diameter

then,

also,

given that,

coordinates of

A = (3,4)

O = (1,2)

and,

let,

B = (x,y)

Now,

AB is the diameter,

therefore,

AO = BO = radius

Therefore,

O is the bisector of AB.

therefore,

by section formula,

sum of coordinate of x axis of A and B

= 2( coordinate of x axis of centre O)

=> 3+ x = 2×1

=> x = 2-3

=> x = -1

Similarly,

sum of coordinate of y axis of A and B

= 2( coordinate of y axis of centre O)

=> 4 + y = 2×2

=> y = 4 -4

=> y = 0

Hence,

the coordinate of other end of diameter,

B = (-1,0)

Answer 2

Step-by-step explanation:

value of x is 3 and y is 5 other end of diameter is (3,5)