Question

3) What is the oxidation state of S in Na2S2?
2.04.1) +2 (20)
a) +
1 8 )-2 c)-1 d) 0.22
A The oxidation state of S in Caro's acid (permono sulphuric acid) H2SOis​

Answer 1

Answer:

(a)- -1 and second ka zero aayega

Answer 2

The oxidation state of 'S' in $Na_2S_2$  is, (-1)

The oxidation state of 'S' in $H_2SO_5$  is, (+6)

Explanation :

Oxidation number : It represent the number of electrons lost or gained by the atoms of an element in a compound.

Oxidation numbers are generally written with the sign (+) and (-) first and then the magnitude.

When the atoms are present in their elemental state then the oxidation number will be zero.

Rules for Oxidation Numbers :

The oxidation number of a free element is always zero.

The oxidation number of a monatomic ion equals the charge of the ion.

The oxidation number of  Hydrogen (H)  is +1, but it is -1 in when combined with less electronegative elements.

The oxidation number of  oxygen (O)  in compounds is usually -2, but it is -1 in peroxides.

The oxidation number of a Group 1 element in a compound is +1.

The oxidation number of a Group 2 element in a compound is +2.

The oxidation number of a Group 17 element in a binary compound is -1.

The sum of the oxidation numbers of all of the atoms in a neutral compound is zero.

The sum of the oxidation numbers in a polyatomic ion is equal to the charge of the ion.

The given compound is, $Na_2S_2$

Let the oxidation state of 'S' be, 'x'

Sodium belongs to group 1. So, its oxidation state is, (+1)

$2(+1)+2x=0\\\\x=-1$

The given compound is, $H_2SO_5$

The oxidation state of 'S' in $Na_2S_2$  is, (-1)

Let the oxidation state of 'S' be, 'x'

In this molecule, the oxidation state of 3 oxygen will be, (-2), oxidation state of 2 oxygen will be, (-1) and the oxidation state of hydrogen will be (+1).

$2(-1)+3(-2)+2(+1)+x=0\\\\x=+6$

The oxidation state of 'S' in $H_2SO_5$  is, (+6)

Learn more about : oxidation number

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