Question

3. What is the resistance of a 200V-60W bulb?
AX. 806 ohm
B. 1320 ohm
C.3.6 ohm​

Answer 1

Answer :

Potential difference of the bulb = 200 V

Power of the bulb = 60 W

Therefore , Resistance of the bulb

= V^2 ÷ P

= [ (200 × 200 ) ÷ 60 ] ohm

= 666.6 ( approx )

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