3) What is the sum of square of the
first four odd natural numbers?
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The series of squares of first n odd numbers takes squares of of first n odd numbers in series.
The series is: 1,9,25,49,81,121…
The series can also be written as − 12, 32, 52, 72, 92, 112….
The sum of this series has a mathematical formula −
n(2n+1)(2n-1)/ 3= n(4n2 - 1)/3
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Answer:
256
Step-by-step explanation:
The first four odd natural numbers is 1, 3, 5, 7
The sum of square of the first four odd natural numbers = (1+3+5+7)^2
= 16^2
= 256
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