Question

3. What is the value of k, if the ots of 2x² - 6x + k=0
are real & equal
​

Answer 1

Answer:

k = 9/2

Step-by-step explanation:

==: 2x² - 6x + k

If roots are real and equal then,

Disciminant (D) = 0

b² - 4ac = 0

(-6)² - 4*2*k = 0

36 - 8k = 0

8k = 36

k = 9/2

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Answer 2

Answer

If the roots of a quadratic equation are real and equal thenDiscriminant

( ${b}^{2}$ - 4ac) of Quadratic equation is zero.

It is given a quadratic equation. 2x2- 6x + k = 0,

the roots of are real and equal.

Therefore Discriminant of Quadratic equation is zero.

b^2 - 4ac =0

The coefficients of 2x2- 6x + k = 0,

a = 2b = -6c = k

To find the value of kb^2 - 4ac =0

(-6)^2 - 4 x 2x k = 0

8k = 36k = 36/8 = 9 /2 = 4.5

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