3. What number must be added to each term of the ratio 8: 11 to make it 4 : 5?
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Let the 1st number be 8x
Let the 2nd number be 11x
■ (8+x) + (11+x) = 4 / 5
cross multiplication:
5(8 + x) = 4(11+x)
40 + 5x = 44 + 4x
5x - 4x = 44 - 40
x = 4
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