Question

3. What should be added to equation 1
to get equation 2
Equation 1 : 04-3a²+2a+5 ; Equation 2 : a-2a-a+7​

Answer 1

Answer:

3a²-4a-2.

Step-by-step explanation:

Let the no. be x

Then, 4-3a²+2a+5 + x = a-2a-a+7  [Transpose 4-3a²+2a+5 to the RHS]

=>x=a-2a-a+7-4+3a²-2a-5

=>x =3a²-4a-2

Thus, 3a²-4a-2 should be added to 4-3a²+2a+5  to get a-2a-a+7.