Question

(3. What sum of money will amount to Rs 18150 in 7/2 years at 6% p.a.?
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Answer 1

Answer:

p= 15239

Step-by-step explanation:

$let \: principal \: p \\ p \times \frac{106}{100} \times \frac{106}{100} \times \frac{106}{100} \times \frac{103}{100} = 18150 \\ or \: p = \frac{18150 \times 100 \times 100 \times 100 \times 100}{106 \times 106 \times 106 \times 103} \\ \: \: \: \: \: \: \: \: = \frac{18150 \times 50 \times 50 \times 50 \times 100}{53 \times 53 \times 53 \times 103} \\ \: \: \: \: \: \: \: = 15239$

Answer 2

Answer:

As it is not mentioned what type of interest to be considered therefore we assume it as simple interest (S.I)

given amount = 18150

w.k.t ., S.I = (p×t×r )/ 100

here it is given as amount so

formula turns out to be A = P + S.I

I.e 18150 = (p×t×r)/100 + p

18150 = (p × 7 × 6) /(2×100) + p

18150 = 42p/ 200 + p

18150 = 242p/ 200 ..... ( taking LCM )

(18150×200) ÷ 242 = p

(18150 × 100) ÷ 121 = p.... (cancellation done by 2).

(150 × 100)= p .... (121× 150 = 18150)

so P= 15000 /-