Question

3.
What value of 'x' will make DE || AB in the given figure?
AD = 8x + 9. CD = x + 3. BE = 3x + 4, CE = X.​

Answer 1

Answer:

i don't no the answer

Step-by-step explanation:

1. uuuuuuuujjhj3u3u3u3uu3u3u3u4uhdhdhhdhhshshvdhdbdvhdhdhdhdhdhhdhdhdhdhdhdueuhehdhdhdurhudueuhfurghduehdiidhudheurhdjdjdhjrhrhrjrjhrhrhrhhrhrhjrjrhhuruuryrrruruururururuuryryryRIururu3u4uu3uu7e7uuyeuu37737uuuy66yyyuuuuuuuu

Answer 2

Given, DE//AB.

$\frac{AD}{DC} = \frac{BE}{EC} \\ \\ \frac{8x + 9}{x + 3} = \frac{3x + 4}{x} \\ \\ {8x}^{2} +9x= {3x}^{2} +13x+12 \\ \\ {5x}^{2} −4x−12=0 \\ \\ {5x}^{2} −10x+6x−12=0 \\ \\ 5x(x−2)+6(x−2)=0 \\ \\ (5x+6)(x−2)=0 \\ \\ x = \frac{ - 6}{5} \: and \: 2$

Therefore x is 2.