Question

3. What weight of N, is present in a
22.4 lit flask at 273°C and
380mm?
1) 8g 2) 11g 3) 7g 4) 14g​

Answer 1

Answer:

3)

Explanation:

PV=nRT

380/760*22.4=n*0.0821*546

n=11.2/44.8

=0.25

So 1 mole is 28g then 0.25 mole is

0.25*28=7g

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