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What will be the total pressure of the gas mixture when 0.5 L of H2 at 0.0
bar and 2.0 L of Oxygen at 0.7 bar are introduced in 1L vessel at 27°C?
Answers
Answer:
P=1.8bar
Explanation:
From the equation Pv = n RT for the two gases. We can write
From the equation Pv = n RT for the two gases. We can write0.8 x 0.5 = nH2 x RT or nH2 = 0.8 x 0.5 / RT
From the equation Pv = n RT for the two gases. We can write0.8 x 0.5 = nH2 x RT or nH2 = 0.8 x 0.5 / RTALSO 0.7 x 2.0 = n02 . RT or n02 = 0.7 x 2 / RT
From the equation Pv = n RT for the two gases. We can write0.8 x 0.5 = nH2 x RT or nH2 = 0.8 x 0.5 / RTALSO 0.7 x 2.0 = n02 . RT or n02 = 0.7 x 2 / RTWhen introduced in 1 L vessel, then
From the equation Pv = n RT for the two gases. We can write0.8 x 0.5 = nH2 x RT or nH2 = 0.8 x 0.5 / RTALSO 0.7 x 2.0 = n02 . RT or n02 = 0.7 x 2 / RTWhen introduced in 1 L vessel, thenPx1L = (n02 + nH2) RT
From the equation Pv = n RT for the two gases. We can write0.8 x 0.5 = nH2 x RT or nH2 = 0.8 x 0.5 / RTALSO 0.7 x 2.0 = n02 . RT or n02 = 0.7 x 2 / RTWhen introduced in 1 L vessel, thenPx1L = (n02 + nH2) RTPutting the values, we get
From the equation Pv = n RT for the two gases. We can write0.8 x 0.5 = nH2 x RT or nH2 = 0.8 x 0.5 / RTALSO 0.7 x 2.0 = n02 . RT or n02 = 0.7 x 2 / RTWhen introduced in 1 L vessel, thenPx1L = (n02 + nH2) RTPutting the values, we getP = 0.4 + 1.4 = 1.8 bar
From the equation Pv = n RT for the two gases. We can write0.8 x 0.5 = nH2 x RT or nH2 = 0.8 x 0.5 / RTALSO 0.7 x 2.0 = n02 . RT or n02 = 0.7 x 2 / RTWhen introduced in 1 L vessel, thenPx1L = (n02 + nH2) RTPutting the values, we getP = 0.4 + 1.4 = 1.8 barHence, the total pressure of the gaseous mixture in the vessel is 1.8 bar