Question

3) Which of the following is the largest in size?
a) Cl^- b) S^2- c) Na d) F^-​

Answer 1

$Cl^{-}$ and $S^{2-}$ has the largest size.

Explanation:

More is the number of electrons present in an atom or ion more will be its radius or size. Electronic configuration of the given ions is as follows.

$Cl^{-} = 1s^{2}2s^{2}2p^{6}3s^{2}3p^{6}$

$S^{2-} = 1s^{2}2s^{2}2p^{6}3s^{2}3p^{6}$

$Na = 1s^{2}2s^{2}2p^{6}3s^{1}$

$F^{-} = 1s^{2}2s^{2}2p^{6}$

Both $Cl^{-}$ and $S^{2-}$ contains 18 electrons. Given neutral sodium atom contain 11 electrons and there are 10 electrons present in $F^{-}$ ion.

This means $Cl^{-}$ and $S^{2-}$ has the largest size.

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Answer 2

Answer:

S^2-

cl^- and S^2- has same size according to electronic configuration but as we know size decrease while going from left to right so S^2- has larger size