Question

3) Which term of the A.P. 3, 14, 25, 36, … will be 99 more than its 25th term​

Answer 1

Answer:

a=3

d=11a+(n+1)d=99+a+24d

3+(n-1)(11)=99+3+24(11)

(n-1)(11)=363

n-1=33

n=34