Question

3) Which term of the G.P. 5, 25, 125, 625, ... is
510​

Answer 1

Step-by-step explanation:

$let \: n \: term \: be \: the \: 510. \\ first \: term \: (a) = 5 \\ common \: ratio(r) = 5 \\ nth \: term \: = a {r}^{n - 1} = 510 \\ \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: = 5 \times {5}^{n - 1} = 510 \\ \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: = {5}^{n} = 510 \\ \\ there \: is \: no \: value \: of \: n \: which \: satisfy \: the \: above \: equation. \\ \\hence \: there \: is \: no \: term \: of \: 510. \\ \\ hope \: it \: will \: he \: will \: help \: you.$