Question

3.
Why dead weight is required to be suspended in this experiment ?
Poliei​

Answer 1

Answer:

The Eqn of the dead weight is

mx¨+2βmx˙+mω02x=mg

so Δx=ω02g or ω22=Δxg

Now λ=ω2πβ=ω02−β22πβ or ωω0=ω02−β22πβ1+(2πλ)2

Thus T=ω2π=ω02−β22πβ=ω0

Explanation:

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