Question

3) With an intial velocity of 20 km/h, a car
accelerated at 8m/s² for 10 seconds?
a) What is the position of the car at
the end of 10 seconds?
What is the velocity of the car at the
end of 10 seconds?

Note: please write and show how u got the answer
​

Answer 1

ANS:

a) s = 455 m

b) *v = 85.5 m/s*

Explanation:

This Question have two parts

LET US FOCUS ON THE GIVEN AREA :D

initial velocity = 20km/h

oh no every other given data is in SI unit

simply convert it

therefore,

*Initial velocity* = 5.55556 m/s

approx = *5.5 m/s*

*accleration = 8 m/s^2*

*time = 10 sec*

therefore,

position of car @10sec = *Total distance it traveled in 10 sec*

Using 2nd eqn of motion

s = ut + 1/2at^2

s = (5.5)(10) + 1/2(8)(10)^2

s = 55 + 400

*s = 455 m*

we can find final velocity for the second part without even using s

by *v = u + at*

v = 5.5 + (8)(10)

v = 5.5 + 80

*v = 85.5 m/s*

can you mark me as BRAINLIEST if this helped :D