Question

3)Write Electronic Configuration of the following element.

i) C(z=6) ii)Na(z=11)

iii)Ti(z=22) iv)S(z=16)
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Answer 1

Answer: Here's your answer!!!!

Explanation:The electronic configuration of Na(11)----->2,8,1 or 1s^2,2s^2 2p^6,3s^1

The electronic configuration of C(6)--------> 2,4 or 1s^2,2s^2 2p^2

The electronic configuration of Ti(22)-----------> 2,8,10,2 or 1s^2,2s^2 2p^6,3s^2 3p^6 3d^2,4s^2

The electronic configuration of S(16)---------> 2,8,6 or 1s^2,2s^2 2p^6, 3s^2 3p^4.

Hope it helps!!!!!

Answer 2

Answer:

1- 1s2 2s2 2 p2

2- 1s2 2 s2 2p6 3s1

3- 1s2 2s2 2p6 3s2 2p6 4s2 3d2

4- 1s2 2s2 2p6 3s2 3p4

Explanation:

According to the laws of quantum mechanics, for systems with only one electron, a level of energy is associated with each electron configuration and in certain conditions, electrons are able to move from one configuration to another by the emission or absorption of a quantum of energy, in the form of a photon.