3)Write Electronic Configuration of the following element.
i) C(z=6) ii)Na(z=11)
iii)Ti(z=22) iv)S(z=16)
Answers
Answer: Here's your answer!!!!
Explanation:The electronic configuration of Na(11)----->2,8,1 or 1s^2,2s^2 2p^6,3s^1
The electronic configuration of C(6)--------> 2,4 or 1s^2,2s^2 2p^2
The electronic configuration of Ti(22)-----------> 2,8,10,2 or 1s^2,2s^2 2p^6,3s^2 3p^6 3d^2,4s^2
The electronic configuration of S(16)---------> 2,8,6 or 1s^2,2s^2 2p^6, 3s^2 3p^4.
Hope it helps!!!!!
Answer:
1- 1s2 2s2 2 p2
2- 1s2 2 s2 2p6 3s1
3- 1s2 2s2 2p6 3s2 2p6 4s2 3d2
4- 1s2 2s2 2p6 3s2 3p4
Explanation:
According to the laws of quantum mechanics, for systems with only one electron, a level of energy is associated with each electron configuration and in certain conditions, electrons are able to move from one configuration to another by the emission or absorption of a quantum of energy, in the form of a photon.