Question

. 3 write five situations for the following where I would a a 7 (8-3) bi (7+2)(10-3 ) be nessacary а,​

Answer 1

Step-by-step explanation:

7+2)(10−3)

[we will open one of the brackets]

7(10−3)+2(10−3)

={(7×10)−(7×3)+{(2×10−2×3)}

={70−21}+{20−6}

=49+14

=63.