Question

3. Write the first three terms of
the AP, when first term a= 5
and common difference d = 3​

Answer 1

Given:-

• a = First term = 5.
• d = common difference = 3.

To find:-

• First three terms of A.P

SolutioN:-

We know that,

General form of A.P = a, a + d, a + 2d, a + 3d.......

In which,

• a is First term.
• d is common difference.

So,

a = 5

d = 3

We want First three terms of A.P

a = 5

a + d = 5 + 3 = 8

a + 2d = 5 + (2×3) = 11

Therefore,

First three terms of A.P are 5 , 8 , 11

So, Our Original A.P is

5 , 8 , 11 .....

Answer 2

Given ,

First term (a) = 5

Common difference (d) = 3

We know that , the nth term of an AP is given by

$\boxed{ \tt{ a_{n} = a + (n - 1)d}}$

Thus ,

$\tt \implies a_{2} = 5 + (2 - 1)3$

$\tt \implies a_{2} = 5 + 3$

$\tt \implies a_{2} = 8$

Similary ,

$\tt \implies a_{3} = 5 + (3 - 1)3$

$\tt \implies a_{3} = 5 + (2)3$

$\tt \implies a_{3} = 5 +6$

$\tt \implies a_{3} = 11$

Therefore , the first three terms ofthe AP are 5 , 8 and 11

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