Math, asked by aanya80, 3 months ago

3/x-1-2/x-2=1/x-3
please answer step by step​

Answers

Answered by dtvbyt36
0

Answer:

ksg gdtd sst again vdgfd de nbbshd bhushan bdbs

Answered by gayathri893346
1
Combine multiplied terms into a single fraction
3


1

1

2


2
=
1


3
3
x

1

1

2
x

2
=
1
x

3
x3​−1−1⋅x2​−2=x1​−3
3


1
+

1

2


2
=
1


3
3
x

1
+

1

2
x

2
=
1
x

3
x3​−1+x−1⋅2​−2=x1​−3
2
Multiply the numbers
3


1
+

1

2


2
=
1


3
3
x

1
+

1

2
x

2
=
1
x

3
x3​−1+x−1⋅2​−2=x1​−3
3


1
+

2


2
=
1


3
3
x

1
+

2
x

2
=
1
x

3
x3​−1+x−2​−2=x1​−3
3
Subtract the numbers
3


1
+

2


2
=
1


3
3
x

1
+

2
x

2
=
1
x

3
x3​−1+x−2​−2=x1​−3
3


3
+

2

=
1


3
3
x

3
+

2
x
=
1
x

3
x3​−3+x−2​=x1​−3
4
Add
3
3
3
to both sides of the equation
3


3
+

2

=
1


3
3
x

3
+

2
x
=
1
x

3
x3​−3+x−2​=x1​−3
3


3
+

2

+
3
=
1


3
+
3
3
x

3
+

2
x
+
3
=
1
x

3
+
3
x3​−3+x−2​+3=x1​−3+3
5
Simplify
Add the numbers
Add the numbers
3

+

2

=
1

3
x
+

2
x
=
1
x
x3​+x−2​=x1​
6
Multiply all terms by the same value to eliminate fraction denominators
3

+

2

=
1

3
x
+

2
x
=
1
x
x3​+x−2​=x1​

(
3

+

2

)
=


1

x
(
3
x
+

2
x
)
=
x

1
x
x(x3​+x−2​)=x⋅x1​
7
Simplify
Distribute
Cancel multiplied terms that are in the denominator
Cancel multiplied terms that are in the denominator
Subtract the numbers
Cancel multiplied terms that are in the denominator
1
Similar questions