Question

3/(x + 1) - 4/(y - 1) = 2 - 1/(x + 1) - 2/(y - 1) = 1​

Answer 1

Step-by-step explanation:

L.H.S= 3/(x+1)-4/(y-1)

(3(y-1)-4(x+1))/(x+1)(y-1)

(3y-3-4x-4)/(x+1)(y-1)

3y-4x-7/(x+1)(y-1)

if the above equation is equal to one then

3y-4x-7/(x+1)(y-1)=1

3y-4x-7=xy-x+y-1

3y-4x-7-(-x+y-1)=xy

3y-y-4x+x-7+1=xy

2y-3x-6=xy. ..................(1)

R.H.S= {2(x+1)-1/(x+1)}-2/(y-1)

(2x+2-1)/(x+1)-2/(y-1)

{(2x+1)(y-1)}-2(x+1)/(x+1)(y-1)

(2xy-2x+y-1)-2x-2/{(x+1)(y-1)}

if the above equation is equal to one then,

2xy-2x+y-1-2x-2=(x+1)(y-1)

2xy-4x+y-3=xy-x+y-1

-4x+x+y+y-.6=2xy-xy

2y-3x-6=xy..................(2)

from (1)&(2) equations L.H.S=R.H.S