Question

3^x+1×9^2x=27^x+2 what is x​

Answer 1

Answer:

Step-by-step explanation:

Given that,

3^x+1 × 9^2x = 27^x+2

3^x+1 × ( 3^2 )^2x = ( 3^3 )^x+2

3^x+1 × 3^4x = 3^3x +6 (∵a^m )^n = a ^mn )

3^x+1+4x = 3^3x +6 ( ∵ Bases are equal , then powers should be add )

3^5x +1 = 3^3x +6

5x +1 = 3x +6 ( ∵ Bases are equal, then powers should be equal )

5x - 3x = 6 - 1 (∵transposing )

2x = 5

x = 5/2 is the answer.