Question

3(x +1/x)2 - 16 (x+ 1/2) + 32=0

Answer 1

▪CORRECT QUESTION :

• $\sf 3 (x+{\dfrac {1}{x}})-16 (x+{\dfrac {1}{2}})+32=0$

▪SOLUTION :

$\longrightarrow\sf 3 (x+{\dfrac {1}{x}})-16 (x+{\dfrac {1}{2}})+32=0$

$\longrightarrow\sf 3x+{\dfrac {3}{x}}-16x+{ \cancel{\dfrac{-16}{2}}}+32=0$

$\longrightarrow\sf 3x+{\dfrac {3}{x}}-16x-8+32=0$

$\longrightarrow\sf 3x+{\dfrac {3}{x}}-16x+24=0$

$\longrightarrow\sf {\dfrac {3x^2+3-16x^2}{x}}+24=0$

$\longrightarrow\sf {\dfrac {-13x^2+3}{x}}+24=0$

$\longrightarrow\sf {\dfrac { - 13x^2+3}{x}}=-24$

• Use cross multiplication :

$\longrightarrow\sf - 13x^2+3=-24x$

$\longrightarrow\underline {\boxed{\bf - 13x^2+24x+3=0}}$

Solve for x :

• For this equation: a = -13, b=24 and c= 3.