Math, asked by yashrathod2006, 8 months ago

3/x + 15/y = 39 & 4/x + 1/y = 38 find x&y?​

Answers

Answered by krajulaxmi9999
2

Answer:

x=0.107

y=1.367

Step-by-step explanation:

by multiplying 2nd equation with 15 and subtracting from 1st equation we get x=0.107

and substuing x values in any of the eq we get y=1.367

Answered by vaibhavlspise2001
1

Step-by-step explanation:

According to the question

3/x+15/y=39

3(1/x+5/y)=39

(1/x+5/y)=39/3

(1/x+5/y)=13

y+5x=13xy..........(1)

now for second equation

4y+x=38xy...........(2)

now multiple (1)by 4

we get

4y +20x=52xy

now subtract (2) from (1)

we get

19x=14xy

y=19/14

now putting value in equation (1)

we get

19/14+5x=13xy

19/14=13(19/14)x-5x

19/14=(13×19-5×14)x/14

19=(247-70)x

19=177x

x=19/177

thank you

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